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KEJAR TERUS SAMPAI DA...

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3. Selesaikanlah pengurutan dengan menggunakan methode BUBLE SORTNPM: 1011754 MODULE 5 = 4Tipe 4 : 40, 99, 60, 30, 45, 16Penyelesaian: Kasus : Tipe 4 : 40, 99, 60, 30, 45, 16 i=0 j=5 -> T: 40, 99, 60, 30, 16, 45j=4 -> T: 40, 99, 60, 16, 30, 45j=3 -> T: 40, 99, 16, 60, 30, 45j=2 -> T: 40, 16, 99, 60, 30, 45j=1 -> T: 16, 40, 99, 60, 30, 45 i=1 j=5 -> F: 16, 40, 99, 60, 30, 45j=4 -> T: 16, 40, 99, 30, 60, 45j=3 -> T: 16, 40, 30, 99, 60, 45j=2 -> T: 16, 30, 40, 99, 60, 45 i=2 j=5 -> T: 16, 30, 40, 99, 45, 60j=4 -> T: 16, 30, 40, 45, 99, 60 i=3 j=5 -> T: 16, 30, 40, 45, 60,...

Sangat Lah MenyenangkanPokok nya Best of the best lahMeski Membuat Wajah Jadi Keri...

include "conio.h"#include "iostream.h"#include "stdio.h"struct siswa { char nis[8]; char nama[30]; int tahun ; } rsiswa[40]; void main(){ int i=0,j; char lg; long uang ; do{ gotoxy(10,5);cout<<"input data siswa "; gotoxy(10,6);cout<<"-----------------"; gotoxy(10,7);cout<<"Nis :";gets(rsiswa[i].nis); gotoxy(10,8);cout<<"Nama :";gets(rsiswa[i].nama); gotoxy(10,9);cout<<"tahun :";cin>>rsiswa[i].tahun; gotoxy(10,10);cout<<"input lagi[Y/T]:";cin>>lg; clrscr();i++; }while(lg=='Y'|| lg=='y'); gotoxy(5,2);cout<<"laporan dta siswa"; gotoxy(5,3);cout<<"-----------------"; gotoxy(5,4);cout<<" No Nis Nama Tahun Uang Sekolah "; gotoxy(5,5);cout<<"-----------------"; for(j=0;ji;j++){ switch(rsiswa[j].tahun){ case 2008:uang=100.000;break; case 2009:uang=175.000;break; case 2010:uang=200.000;break;...

HENDRA BLOG: Tugas Ke 4 Program C++ Hasil Penjualan Barang/Prod...: "#include #include #include #include #include void main() { char kd; char nm[30]; char *nama; char *jenis; int jumlah, jns; float....

#include#include#include#include#include void main(){ char kd; char nm[30]; char *nama; char *jenis; int jumlah, jns; float harga=0; long total; char lagi='y'; clrscr(); while(lagi=='Y'||lagi=='y') {gotoxy(10,5);cout<<"penjualan barang elektronik\n";gotoxy(10,6);cout<<"------------------------------\n";gotoxy(10,7);cout<<"nama pembeli="; cin>>nm;gotoxy(10,8);cout<<"kode barang[A/B/C]="; cin>>kd;gotoxy(10,9);cout<<"jenis bayar[1. tunai/2. kredit]="; cin>>jns;gotoxy(10,10);cout<<"-------------------------------\n"; if((kd=='A'||kd=='a')&&(jns==1)) { nama="televisi"; jenis="tunai"; harga=500000; } else if((kd=='A'||kd=='a')&&(jns==2)) { nama="televisi"; jenis="kredit"; harga=650000; } else if((kd=='B'||kd=='b')&&(jns==1)) { nama="kipas angin"; jenis="tunai"; harga=150000; } else if((kd=='B'||kd=='b')&&(jns==2))...

class Lat3{     public static void main(String Arg[]) throws IOException{     String str;     String nm;     int ttlhrg;     int hrg;     int kde;     int jlh;     BufferedReader Get=new BufferedReader(new     InputStreamReader(System.in));     System.out.print(" Kode        :  "); str=Get.readLine();         kde = Integer.parseInt(str);                 switch(kde){             case 1 : nm= "Televisi" ; hrg= 1750000;             break;             case 2 : nm= "DVD" ; hrg= 750000;    ...

#include "stdio.h" #include "conio.h" #include "iostream.h" void main(){     int p,l,s,pil,r;     float ls,vol;     do {       clrscr();       gotoxy(20,5);cout<<"menu";       gotoxy(20,6);cout<<"1.hitung volume";       gotoxy(20,7);cout<<"2.hitung luas lingkaran";       gotoxy(20,8);cout<<"3.hitung luas pp";       gotoxy(20,9);cout<<"4.keliling lingkarang";       gotoxy(20,10);cout<<"5.keliling persegi panjang";       gotoxy(20,11);cout<<"6.keluar";       gotoxy(20,12);cout<<"pilihan:";cin>>pil;       clrscr();       switch(pil){       case 1:   ...

#include "conio.h"#include "stdio.h"void main(){    int p,l,s; int pil;    float ls,vol;gotoxy(20,1);printf("menu");    printf("\n hitung luas");    printf("\n1 hitung volume");    printf("\n2 pilihan");    scanf("%d",& pil);    if(pil==1){        clrscr();        printf("menghitung luas");        printf("\n lebar`:");        scanf("%d",&p);        printf("\panjang`:");        scanf("%d",&l);        ls=p*l;        printf("luas :%2f",ls);        }else {        clrscr();   ...